Find or replace a substring with String#[]/String#[]=

The String#[] method can match substrings, using a string or RegExp for matching. In the same manner String#[]= can replace the match.

[1] pry(main)> str = "Hello, Georgi"
=> "Hello, Georgi"
[3] pry(main)> str['Georgi']
=> "Georgi"
[4] pry(main)> str['Georgi'] = 'Ivan'
=> "Ivan"
[5] pry(main)> str
=> "Hello, Ivan"

The replacement can make the string longer:

[6] pry(main)> str[/[A-Z]/]
=> "H"
[7] pry(main)> str[/[A-Z]/] = 'Ze'
=> "Ze"
[8] pry(main)> str
=> "Zeello, Ivan"

A nil is returned if there is no match. String#[]= raises an IndexError in this case:

[9] pry(main)> str['H']
=> nil
[10] pry(main)> str['H'] = 'Me'
IndexError: string not matched
from (pry):8:in `[]='

Somehow I’ve missed that one, although it’s currently featured in one of the examples on the official Ruby website!